In a △ABC, ∠A=60∘, ∠B=30∘ and ∠C=90∘.
Then the ratio of the sides AC: BC: AB = _____
1:√3:2
Let us assume the length the of the side opposite to ∠B = x.
In △ABC, we have
sin(∠B)=sin 30∘=xAB⇒12=xAB⇒AB=2x...(i)And,tan 30∘=xBC⇒1√3=xBC⇒BC=√3x....(ii)
∴AC:BC:AB=x:x√3:2x=1:√3:2