Question

In a triangle ABC, $\angle$ ABC + $\angle$ BCA = 120° . Find the value of $\angle$CAB.

• A. ${90}^{\circ }$
• B. ${180}^{\circ }$
• C. ${60}^{\circ }$
• D. ${45}^{\circ }$

Answer 1

The correct option is C

${60}^{\circ }$

We know that the sum of all the angles of a triangle is equal to 180°.

Therefore,

$\angle$ ABC + $\angle$ BCA + $\angle$ CAB = 180⁰

($\angle$ ABC + $\angle$ BCA) + $\angle$ CAB = 180°

(120° ) + $\angle$ CAB = 180° (Given)

$\angle$ CAB = 180° - 120°

$\angle$ CAB = 60°