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Question

In a triangle ABC,C=90o,a=3,b=4 and D is a point on AB, so that BCD=30o. Then the length of CD is

A
1824325
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B
18+24325
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C
824325
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D
None of these
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Solution

The correct option is D None of these
Area of BCD + Area of ACD = Area of ABC

123CDsin30+124CDsin60=123×4

3CD×12+4CD×32=12

CD2(3+43)=12

CD=243+43

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