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Question

In a ΔABC, BD and CE are the altitudes. Prove that ΔADB and ΔAEC are similar. Is ΔCDBΔBEC ? [4 MARKS]

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Solution

Concept: 1 Mark
Application: 3 Marks

In ΔABD and ΔAEC, we have

ADB=AEC [Each equal to 90]

BAD=EAC

So, by AA-criterion of similarity, we have

ΔBDAΔCEA or, ΔADBΔAEC.

Clearly, ΔCDB is not similar to ΔBEC, because they are not equiangular.


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