In a ΔABC, BD and CE are the altitudes. Prove that ΔADB and ΔAEC are similar. Is ΔCDB∼ΔBEC ? [4 MARKS]
Concept: 1 Mark
Application: 3 Marks
In ΔABD and ΔAEC, we have
∠ADB=∠AEC [Each equal to 90∘]
∠BAD=∠EAC
So, by AA-criterion of similarity, we have
ΔBDA∼ΔCEA or, ΔADB∼ΔAEC.
Clearly, ΔCDB is not similar to ΔBEC, because they are not equiangular.