Question

In a triangle ABC, D is a point on BC, such that $\angle$CAD = $\angle$B.
then, $\angle$ADC = $\angle$BAC. State true or false.

• A. True
• B. False

Answer 1

The correct option is A True

Given $\angle CAD=\angle B$
Now, In $△ABD$,
$\angle B+\angle BAD=\angle ADC$ ...........(Exterior angle property)
$\angle CAD+\angle BAD=\angle ADC$
$\angle BAC=\angle ADC$
Hence Proved.