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Question

In a ABC, A=2π3;bc=33 and Δ=932cm2, then a=

A
63cm
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B
9cm
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C
18cm
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D
6cm
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Solution

The correct option is A 9cm
Area =bcsinA2 =c(33+c)2.32=932

Hence,
33c+c2=18
c2+33c18=0

c=33±27+722=33±3112

c=311332
Also given, bc=33
b(311332)=33
b=311+332

Now,
cosA=b2+c2a22bc
=2(99+27)4a22(9927)=2524a2144=12
2524a2=72
4a2=324
2a=18
a=9cm

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