In a triangle ABC, E is the mid point of median AD. Show that ar(BED)=1/4 ar(ABC)

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A B C

E

A D

a r (△ B E D) = \frac{1}{4} a r (△ A B C)

A B C, E

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a r (B E D) = \frac{1}{4} a r (A B C)

In a triangle ABC, E is the mid-point of median AD. Show that ar (BED) = ar (ABC)

In a triangle ABC, E is the mid-point of median AD. Show that ar (ΔBED) = $\frac{1}{4}$ ar(ΔABC) [2 MARKS]

A B C, E

A D

a r e a (B E D) = \frac{1}{4} a r e a (A B C)

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