Question

In a triangle ABC, if $2\angle A=3\angle B=6\angle C$, determine $\angle A,\angle B$ and $\angle C$.

Answer 1

According to the condition in the $△ABC$, $2\angle A=3\angle B=6\angle C$

$\Rightarrow \angle A=3\angle C$ and, $\angle B=2\angle C$

Sum of interior angles of the triangle is ${180}^o$

Hence $\angle A+\angle B+\angle C={180}^o$

$\Rightarrow 3\angle C+2\angle C+\angle C={180}^o$

$\Rightarrow \angle C={30}^o$

$\therefore \angle A={90}^0,\angle B={60}^o,\angle C={30}^o$