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Question
In a △ ABC, if ∠ A = 55 ∘, ∠ B = 40 ∘, find ∠ C.
In a △ ABC, if ∠ A = 55 ∘, ∠ B = 40 ∘, find ∠ C.
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Solution
\( \because \text {Sum of three angles of a triangle is} 180^{\circ }
\therefore in \triangle ABC, \angle A = 55^{\circ}, \angle B = 40 ^{\circ}
But \angle A + \angle B + \angle C = 180 ^{ \circ } (Sum of angles of a triangle)
\Rightarrow 55 ^{ \circ } + 40 ^{ \circ } + \angle C = 180^{ \circ }
\therefore \angle C = 180^{\circ } - 95^{ \circ } = 85^{ \circ } \)
\( \because \text {Sum of three angles of a triangle is} 180^{\circ }
\therefore in \triangle ABC, \angle A = 55^{\circ}, \angle B = 40 ^{\circ}
But \angle A + \angle B + \angle C = 180 ^{ \circ } (Sum of angles of a triangle)
\Rightarrow 55 ^{ \circ } + 40 ^{ \circ } + \angle C = 180^{ \circ }
\therefore \angle C = 180^{\circ } - 95^{ \circ } = 85^{ \circ } \)
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