Question

In a triangle ABC, if $\angle A={55}^o$, if $\angle A={55}^o$ and $\angle B={40}^o$, find $\angle C$.

Answer 1

Using theorem, Sum of interior angles of a triangle is ${180}^o$ .

Hence $\angle A+\angle B+\angle C={180}^o$

$\Rightarrow {55}^o+{40}^o+\angle C={180}^o$

$\Rightarrow \angle C={180}^o-{95}^o$

$\Rightarrow \angle C={85}^o$