In a triangle $A B C ∠ A = 60^{\circ}, ∠ B = 40^{\circ}$ and $∠ C = 80^{\circ}$ If P is the centre of the circumcircle of triangle $A B C$ with radius unity, then the radius of the circumcircle of triangle $B P C$ is

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In a triangle ABC, if b = 2, B = 300 then the area of the circumcircle of triangle ABC in square unit is

The correct option is C 4π Given,b=2,B=300R=b2sinB=22sin300=21⇒R=2Area of circumcircle=πR2=π×(2)2=4π sq.unit

In a triangle ABC, if b = 2, B = $30^{0}$ then the area of the circumcircle of triangle ABC in square unit is

The correct option is C
4π

$G i v e n, b = 2, B = 30^{0} R = \frac{b}{2 s i n B} = \frac{2}{2 s i n 30^{0}} = \frac{2}{1} \Rightarrow R = 2 Area of circumcircle = π R^{2} = π \times (2)^{2} = 4 π s q . u n i t$