Question

In a triangle ABC, if BC=AB and $\angle C={80}^0$ then $\angle B=$ $.....$

• A. ${20}^0$
• B. ${80}^0$
• C. ${60}^0$
• D. ${100}^0$

Answer 1

The correct option is A ${20}^0$

In $△ABC$
$BC=AB$
$\angle C=\angle A={80}^{\circ }$
Sum of angles = 180
$\angle A+\angle B+\angle C=180$
$80+80+\angle B=180$
$\angle B={20}^{\circ }$