In a triangle ABC, if BC=AB and $∠ C = 80^{0}$ then $∠ B =$ $. . . . .$

20^{0}

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80^{0}

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60^{0}

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100^{0}

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Solution

The correct option is A $20^{0}$
In $△ A B C$
$B C = A B$
$∠ C = ∠ A = 80^{\circ}$
Sum of angles = 180
$∠ A + ∠ B + ∠ C = 180$
$80 + 80 + ∠ B = 180$
$∠ B = 20^{\circ}$

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