In a triangle ABC- if a-b-b-c-s-a-s-c- then r1-r2- r3 are in

The correct option is A A.P. a bb c=s as c (a b)(s c)=(b c)(s a) as ac bs+bc=bs ba cs+ac ab+as+bc+cs=2bs+2ac as+cs+ab+bc=2(bs+ac) s ...

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Angle Sum Property

In a triangle...

Question

In a triangle ABC, if $\frac{a - b}{b - c} = \frac{s - a}{s - c},$ then $r_{1}, r_{2}, r_{3}$ are in

A.P.

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G.P.

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H.P.

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none of these

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Solution

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Similar questions

\frac{a - b}{b - c}

\frac{s - a}{s - c},

r_{1}, r_{2}, r_{3}

r_{1}, r_{2}, r_{3}

△ A B C

a < b < c

r

r_{1}, r_{2}, r_{3}

A, B, C

r < r_{1} < r_{2} < r_{3}

△ A B C, r_{1} r_{2} + r_{2} r_{3} + r_{3} r_{1} = \frac{r_{1} r_{2} r_{3}}{r}

\frac{r_{1}}{(s - b) (s - c)} + \frac{r_{2}}{(s - c) (s - a)} + \frac{r_{3}}{(s - a) (s - b)} = \frac{3}{r}

A B C,

(\frac{b - c}{r_{1}}) + (\frac{c - a}{r_{2}}) + (\frac{a - b}{r_{3}}) = 0

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