In a triangle ABC- if cos A - a -cos B - b -cos C - c and a -2- then its area isA- -3B- 2 -3C- -3 - 2D- -3 - 4

The correct option is A √3 The given tirangle is equilateral triangle and its area = √(3) ...

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Standard XII

Mathematics

Summation by Sigma Method

In a triangle...

Question

In a triangle ABC, if $\frac{c o s A}{a} = \frac{c o s B}{b} = \frac{c o s C}{c}$ and a = 2, then its area is

2√3

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√3

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√3/2

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√3/4

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Solution

The correct option is B
√3

The given tirangle is equilateral triangle and its area = $\sqrt{3}$

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In a triangle ABC, if cosAa=cosBb=cosCc and a = 2, then its area is

The correct option is B √3 The given tirangle is equilateral triangle and its area = √3

In a triangle ABC, if $\frac{c o s A}{a} = \frac{c o s B}{b} = \frac{c o s C}{c}$ and a = 2, then its area is

The correct option is B
√3

The given tirangle is equilateral triangle and its area = $\sqrt{3}$