In a triangle ABC, if sinA,sinB,sinC are in A.P, then
A
altitudes are in A.P
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B
altitudes are in H.P
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C
medians are in A.P
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D
medians are in G.P.
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Solution
The correct option is D altitudes are in H.P sinA,sinB,sinC are in A.P ⇒a,b,c are in A.P. 2△=ah1=bh2=ch3 ∴h1:h2:h3=2△a:2△b:2△c =1a:1b:1c ⇒a,b,c are in A.P. ⇒h1,h2,h3 are in H.P.