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Question

In a triangle ABC, if tanA+tan+B+tanC=6 and tanAtanB=2, then the triangle is


A

right angled

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B

isosceles

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C

acute angled

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D

obtuse angled

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Solution

The correct option is C

acute angled


A+B+C=πtan(A+B)=tanCtanC=3tanA+tanC=3(1)

Given
tanAtanB=2(2)
From (1) and (2)
A<90°,B<90°,C<90°


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