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Question

In a triangle ABC, if the radii of ex-circles r1,r2 and r3 are given by r1=8,r2=12 and r3=24, then:

A
in radius r=8
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B
side a=12
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C
side b=16
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D
side c=20
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Solution

The correct options are
B side a=12
C side b=16
D side c=20
a=r1(r2+r3)r1r2+r2r3+r3r1
substituting the values for r1=8,r2=12 and r3=24 we get
a=8×3624=12
b=r2(r3+r1)r1r2+r2r3+r3r1=12×3224=16
c=r3(r1+r2)r1r2+r2r3+r3r1=24×2024=20
Also, r1r2r3=rs2
r=r1r2r3s2
=8×12×24(24)2=4

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