In a triangle ABC, right angled at B, if AB = 3 cm, BC = 4 cm, then the value of AC (in cm) is .

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Solution

The correct option is D 5
By Pythagoras theorem we know that

$A C^{2}$ = $A B^{2}$ + $B C^{2}$

So, $A C^{2}$ = $3^{2}$ + $4^{2}$ = 9 + 16 = 25

So, AC = 5

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