In a triangle ABC, right angled at B, tan A is equal to the ratio of AB and AC

True

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False

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Solution

The correct option is B
False

Tan A is a trigonometric ratio representing height divided by the base of the right triangle.

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Similar questions

In a right triangle ABC, right angled at B, cot A represents the product of BC and CA.

tan A = cot B

\sqrt{2}

\frac{t a n A}{1 + t a n^{2} A},

$Δ A B C$ is right angled at C. Then $s e c B = \frac{A B}{B C}$

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