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Question
In a △ABC, the sides AB and AC have been produced to D and E. Bisectors of ∠CBD and ∠BCE meet at O. If ∠A = 64∘, then ∠BOC is:
In a △ABC, the sides AB and AC have been produced to D and E. Bisectors of ∠CBD and ∠BCE meet at O. If ∠A = 64∘, then ∠BOC is:
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Solution
The correct option is B 58°
∠OBC = 90∘ - A2
∠OBC = 90∘ - 64∘2 = 58∘
58°
∠OBC = 90∘ - A2
∠OBC = 90∘ - 64∘2 = 58∘
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