In a ABC- the value of 1-tan B 2 tan C 2 - 2a a-b-c is equal to

The correct option is B 2a a+b+c Now, 1 tan B 2 #160;tan C 2 #160; =1 √(( s a ) ( s c ) #160; s(s b) #160;)×√(( s a ) ( s b ) ...

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Circular Measurement of Angle

In a ABC, t...

Question

In a $△ A B C$ , the value of $1 - tan \frac{B}{2} tan \frac{C}{2} = \frac{2 a}{a + b + c}$ is equal to

\frac{2 a}{a + b + c}

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\frac{2}{a + b + c}

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\frac{2 a}{a - b + c}

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None of these

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In triangle ABC, $1 - t a n \frac{B}{2} . t a n \frac{C}{2}$ is equal to

In a $△ A B C$ , if $t a n \frac{A}{2} = \frac{5}{6} a n d t a n \frac{B}{2} = \frac{20}{37}$ ,then

∣ ∣ ∣ ∣ \begin{matrix} a - b - c & 2 a & 2 a 2 b & b - c - a & 2 b 2 c & 2 c & c - a - b \end{matrix} ∣ ∣ ∣ ∣

= (a + b + c) (x + a + b + c)^{2}, x \neq 0

a + b + c \neq 0

x

(a + b)^{2} + (a - b)^{2}

2 a + 2 b

2 a - 2 b

2 a^{2} + 2 b^{2}

2 a^{2} + 2 b^{2}

\to a \times \to b = \to c, \to b \times \to c = 2 \to a

[\to a \to b \to c] = 2

\to c \times \to a =

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