In a triangle ABC- the value of the expression -r - 0n nCrar-bn - r-cos rB - n - rA is equal to

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1st Law of Thermodynamics

In a triangle...

Question

In a triangle $A B C$ , the value of the expression $n \sum r = 0^{n} C_{r} a^{r} . b^{n - r} . cos (r B - (n - r) A)$ is equal to

c^{n}

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zero

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a^{n}

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b^{n}

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Solution

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Similar questions

{a_{n}}, {b_{n}}, {c_{n}}

(i) a_{n} + b_{n} {+ c}_{n} = 2 n + 1

(i i) a_{n} b_{n} + b_{n} c_{n} + {+ c}_{n} a_{n} = 2 n - 1

(i i i) a_{n} b_{n} c_{n} = - 1

(i v) a_{n} < b_{n} < c_{n}

lim n \to \infty n a_{n}

A_{n} = 2 n \sum r = 1 sin ({sin}^{- 1} x^{3 r - 2}), B_{n} = 2 n \sum r = 1 cos ({cos}^{- 1} x^{3 r - 1}), C_{n} = 2 n \sum r = 1 tan ({tan}^{- 1} x^{3 r}), n \in N, n \geq 3

| x | \leq 1

n

\frac{a^{n + 1} + b^{n + 1}}{a^{n} + b^{n}}

A . M

a

b

n \sum s = 1 {s \sum r = 1 r} = a n^{3} + b n^{2} + c n

n \sum r = 1 T_{r} = 5 n + 2

n \sum r = 1 T_{r}^{2} = a n^{3} + b n^{2} + c n + d

d + b + c

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