Question

In a triangle, each of the bigger angles is twice the third angle. Find the angles.

Answer 1

Let the third angle be $x^o$ in the $△ABC$

The each bigger angle will be $2x^o$

We know that sum of angles of a triangle is ${180}^o$ .

$\Rightarrow 2x^o+2x^o+x^o={180}^o$

$\Rightarrow 5x^o={180}^o$

$\Rightarrow x^o={36}^0$

$\therefore$ Angles are ${36}^o,{72}^o,{72}^o$