In a triangle, exterior angle measures 120°. If one of the interior opposite angle measure 50°, then what is the value of the other interior opposite angle?

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Solution

We know that, the exterior angle is equal to the sum of the interior opposite angles.
Let the unknown interior angle be $x$ .
$x + 50^{\circ} = 120^{\circ} x = 120^{\circ} - 50^{\circ} = 70^{\circ} x = 70^{\circ}$
The other interior angle is 70°.

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In a triangle, exterior angle measures 120°. If one of the interior opposite angle measure 50°, then what is the value of the other interior opposite angle?

We know that, the exterior angle is equal to the sum of the interior opposite angles. Let the unknown interior angle be x. x+50∘=120∘x=120∘−50∘=70∘x=70∘ The other interior angle is 70°.

We know that, the exterior angle is equal to the sum of the interior opposite angles.
Let the unknown interior angle be $x$ .
$x + 50^{\circ} = 120^{\circ} x = 120^{\circ} - 50^{\circ} = 70^{\circ} x = 70^{\circ}$
The other interior angle is 70°.