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Byju's Answer
Standard VII
Mathematics
Angles
In a PQR, ...
Question
In a
△
P
Q
R
,
L
and
M
are two points on the base
Q
R
such that
∠
L
P
Q
=
∠
Q
R
P
and
∠
R
P
M
=
∠
R
Q
P
.Prove that
Q
L
×
R
M
=
P
L
×
P
M
Open in App
Solution
In
△
P
Q
L
and
△
R
M
P
∠
L
P
Q
=
∠
Q
R
P
(given)
∠
R
Q
P
=
∠
R
P
M
(given)
⇒
△
P
Q
L
∼
△
R
M
P
(AA similarity)
⇒
P
Q
R
P
=
Q
L
P
M
=
P
L
R
M
⇒
Q
L
×
R
M
=
P
L
×
P
M
Hence proved.
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Similar questions
Q.
In a triangle PQR, L and M are two points on the base QR, such that
∠
L
P
Q
=
∠
Q
R
P
and
∠
R
P
M
=
∠
R
Q
P
. Prove that: [4 MARKS]
i)
Δ
P
Q
L
∼
Δ
R
P
M
ii)
Q
L
×
R
M
=
P
L
×
P
M
iii)
P
Q
2
=
Q
R
×
Q
L
Q.
In a triangle PQR, L and M are two points on the base QR such that
∠
L
P
Q
=
∠
Q
R
P
and
∠
R
P
M
=
∠
R
Q
P
Prove that: [4 MARKS]
(i)
Δ
P
Q
L
∼
Δ
R
P
M
(ii)
Q
L
×
R
M
=
P
L
×
P
M
(iii)
P
Q
2
=
Q
R
×
Q
L
Q.
In a triangle PQR, L and M are two points on the base QR, such that
∠
L
P
Q
=
∠
Q
R
P
and
∠
R
P
M
=
∠
R
Q
P
. Prove that
P
Q
2
=
Q
R
×
Q
L
Q.
In a triangle PQR, L and M are two points on the base QR, such that
∠
L
P
Q
=
∠
Q
R
P
and
∠
R
P
M
=
∠
R
Q
P
. Prove that
△
P
Q
L
∼
△
R
Q
P
Q.
In the adjoining figure, PQ
=
PR and QL
=
MR. Prove that PL
=
PM.
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