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If Two Sides of a Triangle Are Unequal, Then the Angle Opposite to the Greater Side Is Greater Than Angle Opposite to the Smaller Side

In a triangle...

Question

In a triangle shown below, AB+AD=BC+CD, If AB=Y, BC=a and CD= d, then y equal :

\frac{a d}{2 a + d}

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d-a

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a+d

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\frac{1}{2} a

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Solution

The correct option is A $\frac{a d}{2 a + d}$

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Similar questions

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In the given figure, if AD = BC and AD || BC, then

In a trapezium ABCD, if AB || CD then $(A C^{2} + B D^{2})$ = ?

(a) $B C^{2} + A D^{2} + 2 B C . A D$

(b) $A B^{2} + C D^{2} + 2 A B . C D$

(d) $B C^{2} + A D^{2} + 2 A B . C D$

A B | | C D

A D = B C

∠ C = 76^{\circ}

∠ D

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