Question

In a triangle the height is double the base and the area is 400 $c{m}^2$. Find the length of the base and height.

Answer 1

$Areaoftriangle=\frac{1}{2}\times base\times height$

$Base=x$

$height=2x$

$=\frac{1}{2}\times x\times 2x=400$

$=x^2=400$

$x=\sqrt{400}=20$

$base=20cm$

$height=40cm$