In a triangle, the perpendicular from vertex to the base bisects the base. The triangle is
Isosceles Triangle
In △ADB and △ADC
AD = AD [common]
∠ADB = ∠ADC [Equal to 90∘]
BD = DC [Given]
Therefore, △ADB ≅ △ADC [SAS Criteria]
By CPCT, AB = AC
Therefore, △ABC is Isoceles Triangle.