In a triangle with sides a, b and c, let s be the semiperimeter and p be the perimeter. The value of $\frac{p}{s}$ is ___.

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Solution

p = a + b + c
s = $\frac{a + b + c}{2}$
So, $\frac{p}{s}$ = 2

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In a triangle with sides a, b and c, let s be the semiperimeter and p be the perimeter. The value of ps is ___.

p = a + b + c s = a+b+c2 So, ps = 2

In a triangle with sides a, b and c, let s be the semiperimeter and p be the perimeter. The value of $\frac{p}{s}$ is ___.

p = a + b + c
s = $\frac{a + b + c}{2}$
So, $\frac{p}{s}$ = 2