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Question

In a triaxial test at failure, major principal stress was 180 kPa, minor principal stress was 100 kPa, and pore pressure was 20 kPa. The tangent of the angle of shearing resistance of the sandy soil tested is

A
1/3
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B
2/7
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C
1/2
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D
1/6
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Solution

The correct option is A 1/3
Major principal stress:
¯¯¯σ1=σ1u=18020=160 kPa
Minor principal stress:
¯¯¯σ3=σ3u=10020=80 kPa
For sand,
c=0
σ1=σ3 tan2(45o+ϕ2)
Thus on solving ϕ=19.47o
And tan ϕ=0.353
So, nearest option is (a)

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