In a triaxial test at failure, major principal stress was 180 kPa, minor principal stress was 100 kPa, and pore pressure was 20 kPa. The tangent of the angle of shearing resistance of the sandy soil tested is
A
1/3
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B
2/7
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C
1/2
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D
1/6
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Solution
The correct option is A1/3 Major principal stress: ¯¯¯σ1=σ1−u=180−20=160kPa
Minor principal stress: ¯¯¯σ3=σ3−u=100−20=80kPa
For sand, c=0 σ1=σ3tan2(45o+ϕ2) Thusonsolvingϕ=19.47o Andtanϕ=0.353
So, nearest option is (a)