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Question

In a two-digit number, if two is added to the digit in ten's place, the number formed will have ten's place digit which is 0.6 times the original one and unit's digit which is four times more than the initial digit in unit's place. The difference between the digits in ten's place and that in unit's place is


A

0.

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B

Positive and divisible by 4

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C

Negative and divisible by 4

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D

Positive and divisible by 5

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E

None of these

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Solution

The correct option is E

None of these


10(a + 2) + b = 10 (0.6a) + 5b

4a - 4b = - 20

a - b = - 5


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