In a two digit number the digit at the units place is double the digit in the tens place. The number exceeds sumof its digit by 18. Find the number

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Solution

Let the digit in tens place be x. Then the digit in units place is 2x.
The number is actually 10(x)+ +2x = 12x
Sum of digits = x+ 2x = 3x.
Number exceeds sum of digits by 18.
This means 12x=3x+18
=> 12x-3x = 18
=> 9x = 18
=> x = 2
So the number is 24
Answer: 24

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In a two digit number the digit at the units place is double the digit in the tens place. The number exceeds sumof its digit by 18. Find the number

Let the digit in tens place be x. Then the digit in units place is 2x. The number is actually 10(x)+ +2x = 12x Sum of digits = x+ 2x = 3x. Number exceeds sum of digits by 18. This means 12x=3x+18 => 12x-3x = 18 => 9x = 18 => x = 2 So the number is 24 Answer: 24

Let the digit in tens place be x. Then the digit in units place is 2x.
The number is actually 10(x)+ +2x = 12x
Sum of digits = x+ 2x = 3x.
Number exceeds sum of digits by 18.
This means 12x=3x+18
=> 12x-3x = 18
=> 9x = 18
=> x = 2
So the number is 24
Answer: 24