In a two-digit number, the digit at the units place is thrice the digit in the tens place.The number exceeds the sum of its digits by 27. Find the number.

(Answer:39)

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Solution

Digit in the tens place =x then digit at unit place be 3x
number is =10x+3x=13x....... (1)
sum of digits=x+3x=4x
given the number exceeds sum of it's digits by 27.
Then, 13x=4x+27
(13-4)x=27
9x=27
x=3
Then the number become from (1)
13x=13×3=39
The number is 39

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In a two-digit number, the digit at the units place is thrice the digit in the tens place.The number exceeds the sum of its digits by 27. Find the number. (Answer:39)

Digit in the tens place =x then digit at unit place be 3x number is =10x+3x=13x....... (1) sum of digits=x+3x=4x given the number exceeds sum of it's digits by 27. Then, 13x=4x+27 (13-4)x=27 9x=27 x=3 Then the number become from (1) 13x=13×3=39 The number is 39

In a two-digit number, the digit at the units place is thrice the digit in the tens place.The number exceeds the sum of its digits by 27. Find the number.

(Answer:39)

Digit in the tens place =x then digit at unit place be 3x
number is =10x+3x=13x....... (1)
sum of digits=x+3x=4x
given the number exceeds sum of it's digits by 27.
Then, 13x=4x+27
(13-4)x=27
9x=27
x=3
Then the number become from (1)
13x=13×3=39
The number is 39