Question

In a two digit number, the digit at unit place is $x$ at the digit at tens place is $5$, then the new number obtained by interchanging the digits of that number is

• A. $50x+5$
• B. $10x+5$
• C. $x+50$
• D. $5x+4$

Answer 1

The correct option is B $10x+5$

The digit in units place is $x$

The digit in tens place is $5$

So the number is $50+x$

If the number is reversed,

The units digit is $5$

The tens digit is $x$

So the number is $10x+5$