In a two digit number the digit in the unit place is twice of the digit in the 10th if the digits are reversed the new number is 27 more then the given number find the number

Open in App

Solution

let u=units digit
let t=tens digit
u=2t

digits reversed:
10u+t=10t+u+27
20t+t=10t+2t+27
9t=27
t=3
u=2t=6
number:36

Suggest Corrections

Similar questions

Q. In a two digit number, the digit in the unit place is twice of the digit in the tenth place. If the digits are reversed, the new number is

27

more than the given number. Find the number.

In a two-digit number, the units digit is twice the ten's digit. If $27$ is added to the number, the digits are reversed. Find the number.

Question 99

Solve the following:

In a two-digit number, digit in unit's place is twice the digit in ten's place. If 27 is added to it, digits are reversed. Find the number.

The digit in the tens place of a two-digit number is four times the digit in the units place. When the digits are reversed, the number obtained is 27 less than the original numbers. Find the original number.

Q. In a two-digit number, the units digit is twice the tens digit. If 27 is added to the number, the digits interchange their places. Find the number.

Join BYJU'S Learning Program

In a two digit number the digit in the unit place is twice of the digit in the 10th if the digits are reversed the new number is 27 more then the given number find the number

let u=units digit let t=tens digit u=2t digits reversed: 10u+t=10t+u+27 20t+t=10t+2t+27 9t=27 t=3 u=2t=6 number:36

let u=units digit
let t=tens digit
u=2t

digits reversed:
10u+t=10t+u+27
20t+t=10t+2t+27
9t=27
t=3
u=2t=6
number:36