Question

In a two digit number the sum of the digits is 7. If the number with the order of the digits reversed is 28 greater than twice the units digit of the original number, find the number.

Answer 1

Let the original number be 10(7-x)+x
Here, X is the one's digit and (7-X) is the tens digit which is why we multiply it with 10.
The reversed number would be 10x+(7-x)
We know, 10x+(7-x)=28+2x
=>10x+7-x=28+2x
=>10x-2x-x=28-7
=>7x=21
=>x=3
Hence, the original number is 10(7-3)+3= 43.