In a two – digit number, the sum of the digits is equal to 10. The ratio of the digit at the unit’s place to that of the digit at ten’s place is 4:1. What is the number?

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None of these

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Solution

The correct option is E
None of these

Let the ten's digits be x. then, unit's digit = 4x

$∴ x + 4 x = 10 \Leftrightarrow 5 x = 10 \Leftrightarrow x = 2.$

So, tens, digit = 2, unit's digit = 8

Hence, the required number is 28

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In a two – digit number, the sum of the digits is equal to 10. The ratio of the digit at the unit’s place to that of the digit at ten’s place is 4:1. What is the number?

The correct option is E None of these Let the ten's digits be x. then, unit's digit = 4x ∴x+4x=10⇔5x=10⇔x=2. So, tens, digit = 2, unit's digit = 8 Hence, the required number is 28

The correct option is E
None of these

Let the ten's digits be x. then, unit's digit = 4x

$∴ x + 4 x = 10 \Leftrightarrow 5 x = 10 \Leftrightarrow x = 2.$

So, tens, digit = 2, unit's digit = 8

Hence, the required number is 28