In a two-digit number, the tens digit is twice the unit digit. If the sum of its digits is $9$ , find the number.

Open in App

Solution

Let the unit digit be $x$
So, the tens digit will be $2 x$
Also, $x + 2 x = 9$
$\to 3 x = 9$
$\to x = 3$
So, the number is $10 (2 x) + x = 21 x = 63$

Suggest Corrections

Similar questions

Q. In a two-digit number, the units digit is twice the tens digit. If 9 is added to the number, the digits interchange their places. Find the number.

Q. Unit digit of a two digit number is three times its tens digit. If the unit digit is 6. Find the number.

The sum of the digits of a two-digit number is $9.$ If the digit in tens place is twice the digit in the units place, then the number is:

In a three digit number the hundreds digit is twice the tens digit while the units digit is thrice the tens digit also the sum of its digits is 18 find the number

Q. The sum of the digits of a two digit number is 6 and it's tens digit is twice it's unit digit. Find the number.

Join BYJU'S Learning Program

In a two-digit number, the tens digit is twice the unit digit. If the sum of its digits is 9, find the number.

Let the unit digit be x So, the tens digit will be 2x Also, x+2x=9 →3x=9 →x=3 So, the number is 10(2x)+x=21x=63

In a two-digit number, the tens digit is twice the unit digit. If the sum of its digits is $9$ , find the number.

Let the unit digit be $x$
So, the tens digit will be $2 x$
Also, $x + 2 x = 9$
$\to 3 x = 9$
$\to x = 3$
So, the number is $10 (2 x) + x = 21 x = 63$