In a two-digit number, the units digit is twice the ten's digit. Also, if 27 is added to the number, the digits interchange there places. Find the number.
36
Let the digit in the units place be x and digit in the tens place be y.
Units digit = twice the tens digit [Given]
⇒ x = 2y . . . . (1)
Let the two digit number be 10y + x.
Number obtained by reversing the digits = 10x + y
Number + 27 = Number obtained by interchanging the digits [Given]
∴ 10y + x + 27 = 10x + y
⇒9x−9y=27
⇒x−y=3 . . . . (2)
Putting x = 2y in equation (2), we get,
2y - y = 3 ⇒ y = 3
Putting y = 3 in equation (2), we get,
x - 3 = 3 ⇒ x = 6
10y + x = 10 × 3 + 6 = 36
Hence, the number is 36.