In a two-digit number, the units digit is twice the ten's digit. If 27 is added to the number, the digits are reversed. Find the number.
36
Let the digit in the units place be x and digit in the tens place be y.
According to first condition
⇒ x = 2y . . . . (1)
∴ the two digit number is 10y + x.
When 27 is added, the digits are reversed.[Given]
∴ 10y + x + 27 = 10x + y
⇒9x−9y=27
⇒x−y=3 . . . . (2)
Putting x = 2y in equation (2), we get,
2y - y = 3 ⇒ y = 3
Putting y = 3 in equation (2), we get,
x - 3 = 3 ⇒ x = 6
10y + x = 10 × 3 + 6 = 36
Hence, the number is 36.