In a two digit number, then ten's digit is three times the unit's digit. When the number is decreased by 54, the digit are reversed. Find the number.

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Solution

$L e t x b e t h e u n i t d i g i t T e n^{'} s d i g i t = 3 x N o = 3 x (10) + x = 31 x R e v e r s e d n o = 10 x + 3 x = 13 x 31 x - 54 = 13 x 31 x - 13 x = 54 18 x = 54 x = 3 T e n s d i g i t = 9 N o = 93$

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In a two digit number, then ten's digit is three times the unit's digit. When the number is decreased by 54, the digit are reversed. Find the number.

LetxbetheunitdigitTen′sdigit=3xNo=3x(10)+x=31xReversedno=10x+3x=13x31x−54=13x31x−13x=5418x=54x=3Tensdigit=9No=93

$L e t x b e t h e u n i t d i g i t T e n^{'} s d i g i t = 3 x N o = 3 x (10) + x = 31 x R e v e r s e d n o = 10 x + 3 x = 13 x 31 x - 54 = 13 x 31 x - 13 x = 54 18 x = 54 x = 3 T e n s d i g i t = 9 N o = 93$