In a two digits no the sum of digits is 8 if we add 18 to those digits the digits are inter changed find the no

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Solution

Let the number be 10x+y.

Here x + y = 8 …(1)

10x+y - (10y+x) = 18 … (2)

(2) becomes 10x+y - 10y-x = 18 or

9x -9y = 18, or

x - y = 2 … (3)

x+y = 8 … (1). Add (1) and (3) to get

2x = 10, or x = 5. The y = 8–5 = 3

Hence the number is 35. The reverse is 53 and 53–35 = 18.

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In a two digits no the sum of digits is 8 if we add 18 to those digits the digits are inter changed find the no

Let the number be 10x+y. Here x + y = 8 …(1) 10x+y - (10y+x) = 18 … (2) (2) becomes 10x+y - 10y-x = 18 or 9x -9y = 18, or x - y = 2 … (3) x+y = 8 … (1). Add (1) and (3) to get 2x = 10, or x = 5. The y = 8–5 = 3 Hence the number is 35. The reverse is 53 and 53–35 = 18. LIKE IF SATISFIED