In a uniform electric field, when we move from origin to x=1m, the potential charges by 10V. Which of the following can be a possible magnitude of the electric field.
A
10Vm−1
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B
15Vm−1
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C
5Vm−1
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D
20Vm−1
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Solution
The correct option is D20Vm−1 Electric field is given by, E=Vd...(1)
Given, V=10V and d=1m
Now, from equation (1) we get,
Ex=101
Ex=10Vm−1
As, E≥Ex
So the possible magnitude of the electric field will be,