In a vacuum, a five-rupee coin, a feather of a sparrow bird and a mango are dropped simultaneously from the same height. The time taken by them to reach the bottom is $t_{1}$ , $t_{2}$ and $t_{3}$ respectively. In this situation, we will observe that:

t_{1} > t_{2} > t_{3}

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t_{1} > t_{3} > t_{2}

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t_{3} > t_{1} > t_{2}

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t_{1} = t_{2} = t_{3}

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Solution

The correct option is D $t_{1} = t_{2} = t_{3}$
The acceleration due to gravity $g$ is independent of the mass $m$ of an object. Hence, if the other forces like the air resistance are neglected as in the case of a vacuum, The time $t_{1}$ , $t_{2}$ and $t_{3}$ for a five-rupee coin, a feather of a sparrow bird and a mango respectively to reach the ground if dropped simultaneously from the same height will be same.
Thus, we get $t_{1}$ = $t_{2}$ = $t_{3}$ .

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In a vacuum, a five-rupee coin, a feather of a sparrow bird and a mango are dropped simultaneously from the same height. The time taken by them to reach the bottom is t1, t2 and t3 respectively. In this situation, we will observe that:

In a vacuum, a five-rupee coin, a feather of a sparrow bird and a mango are dropped simultaneously from the same height. The time taken by them to reach the bottom is $t_{1}$ , $t_{2}$ and $t_{3}$ respectively. In this situation, we will observe that: