wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

In a vernier calipers 10 smallest divisions of the vernier scale are equal to 9 smallest divisions of the main scale. If the smallest division of the main scale is half millimeter, then the vernier constant is:

A
0.005 mm
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
0.05 mm
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
0.5 mm
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
0.01 mm
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B 0.05 mm
MSD = Main scale divisions
VSD = Vernier scale divisions
From the data given in the question,
1 MSD=0.5 mm and, 10 VSD = 9 MSD
1 VSD=910MSD=910×0.5=0.45 mm
Vernier constant(VC) or Least count(LC),
=1 MSD1 VSD=0.50.45=0.05 mm
Hence, option (b) is the correct answer.

flag
Suggest Corrections
thumbs-up
3
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Vernier Caliper and Screw Gauge
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon