Question

In a World Cup final match against Srilanka, for six times Sachin Tendulkar hits a six out of $30$ balls he plays. What is the probability that in a given throw the ball does not hit a six?

• A. $\frac{1}{4}$
• B. $\frac{5}{4}$
• C. $\frac{4}{5}$
• D. $\frac{3}{4}$

Answer 1

Answer: (C)

$\frac{4}{5}$

Total number of balls played by Sachin Tendulkar is $30$.

$\Rightarrow n\left(S\right)=30$

In $30$ balls he hits six $6$ times.

Let $A$ be the event that the ball thrown hits six.

$\Rightarrow n\left(A\right)=6$

Therefore the probability that the ball thrown hits six, $P\left(A\right)=\frac{n\left(A\right)}{n\left(S\right)}$

$P\left(A\right)=\frac{6}{30}=\frac{1}{5}$

Hence the probability that the ball thrown does not hit six is $P\left(A^{\prime }\right)$.

We know that $P\left(A^{\prime }\right)=1-P\left(A\right)$

$=1-\frac{1}{5}=\frac{4}{5}$

$\therefore P\left(A^{\prime }\right)=\frac{4}{5}$

Hence the probability that the ball thrown does not hit six is $\frac{4}{5}$.