Question

In a YDSE setup light of wavelength $4000\stackrel{\circ }{A}$ is used. Distance of screen from the slits is $2m$ and distance between slits is $1mm$. There are three slabs slab $1$ (thickness $2mm,\mu =2),slab2$ (thickness $1mm,\mu =3)$, slab $3$ (thickness $4mm,\mu =\frac{3}{2})$.

(A) If slab $1$ is placed in front of slit $S_1$	(P) Central maxima at $C$
(B) If the slab $2$ is placed in front of slit $S_2$ along with condition (A)	(Q) Central maxima above $C$
(C) If slab $3$ is placed in front of slab $1$ along with condition (B)	(R) Fringe width is equal to $0.8mm$
	(S) No. of fringes crossing central maxima as a result of slab placing is $5000$

Answer 1

Given YDSE $\lambda =400\mathring{A}D=2md=1mm$

For slab $1$ thickness $2mm,\mu =2$

Slab $2$ thickness $1mm,\mu =3$

Slab $3$thickness $4mm,\mu =\frac{3}{2}$

(A) If slab $1$ is place in front of slit $S_1$ (Q) Central maxima above C

(B) If the slab $2$ is placed in front (S) No fringes crossing central maxima

of slit $S_2$ along with condition. a result of slab placing is $5000$

(C) If slab $3$ is placed in front of a slab (P) Central maxima at C

$1$ along with condition (B)