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Question

In a Young's double slit experiment for interference of light, the slits are 0.2 cm apart and are illuminated by yellow light(λ=600 nm). What would be the fringe width on a screen placed 1 m from the plane of slits if the whole system is immersed in water of refractive index 43.

A
0.225 mm
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B
2.25 mm
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C
0.125 mm
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D
1.25 mm
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Solution

The correct option is A 0.225 mm
Given,
λ=600 nm=6×107 m
D=1 m
d=0.2 cm=2×103 m

As the apparatus is dipped in water(μ=43) :
λnew=λμ=6×10743 m=4.5×107 m

βnew=λnewDd=4.5×107×12×103=2.25×104 m=0.225 mm

Hence, (C) is the correct answer.

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