In a Young-s double slit experiment let A and B be two slits- Films of thicknesses tA and tB and refractive indices -A and -B- are placed in front of A and B respectively- If -AtA-BtB- the central maximum will

The correct option is D option(C), if t_B gt;t_A ;option (B), if t_B lt; t_A Extra path difference due to film of thickness t_A is ( ...

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Byju's Answer

Standard XII

Physics

Intensity Amplitude Relationship

In a Young's ...

Question

In a Young's double slit experiment let $A$ and $B$ be two slits. Films of thicknesses $t_{A}$ and $t_{B}$ and refractive indices $μ_{A}$ and $μ_{B}$ , are placed in front of $A$ and $B$ respectively. If $μ_{A} t_{A} = μ_{B} t_{B}$ , the central maximum will

not shift

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shift towards

A

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shift towards

B

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option(C), if

t_{B} > t_{A}

;option (B), if

t_{B} < t_{A}

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Solution

The correct option is D option(C), if $t_{B} > t_{A}$ ;option (B), if $t_{B} < t_{A}$
Extra path difference due to film of thickness $t_{A}$ is $(μ_{A} - 1) t_{A}$
Extra path difference due to film of thickness $t_{B}$ is $(μ_{B} - 1) t_{B}$
Hence, extra path difference introduced due to films: $(μ_{A} - 1) t_{A} - (μ_{B} - 1) t_{B} = t_{B} - t_{A}$ since given $μ_{A} t_{A} = μ_{B} t_{B}$
If $t_{A} > t_{B}$ , the central maximum will shift towards A and if $t_{B} > t_{A}$ , the central maximum will shift towards B

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In a Young's double slit experiment let A and B be two slits. Films of thicknesses tA and tB and refractive indices μA and μB, are placed in front of A and B respectively. If μAtA=μBtB, the central maximum will

In a Young's double slit experiment let $A$ and $B$ be two slits. Films of thicknesses $t_{A}$ and $t_{B}$ and refractive indices $μ_{A}$ and $μ_{B}$ , are placed in front of $A$ and $B$ respectively. If $μ_{A} t_{A} = μ_{B} t_{B}$ , the central maximum will