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Question

# In a Young's double slit experiment shown in the figure, a parallel beam of light is incident on the slits from a medium of refractive index μ1.The wavelength of light in this medium is λ1. A transparent slab of thickness t and refractive index μ3 is put in front of one slit.The refractive index of medium between the screen and the plane of the slits is μ2.Find the phase difference between the light waves at point O (symmetrical, relative to the slits) .

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Solution

## Given,For Young Double Slit model,refractive index =μWavelength of light in the medium=λ1Thickness=tRefractive index=μ3 (in transparent slab)The refractive index of medium between the screen and the plane of the slits =μ2Finding phase difference between the light wave at point OPath difference of Young double slit model, =2πλ(xdD)Phase difference =2πλ×pathdifference=2πλ×2πλ(xdD)=4π2λ21(xdD)Phase difference of Young double slit model is independent of refractive index.

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